Telephotography of restricted areas

Dreaded Trigonometry

I promised no diagrams. So sue me. Luckily, all you need to remember from middle school are the properties of similar triangles. Similar triangles have the same angles. Their dimensions will be ratios of each other. So we have:

[Focal Plane] / [Field of View] = [Focal Length] / [Distance to Target]

similar triangles

This diagram works for horizontal or vertical field of view provided you use the proper dimensions for the focal plane. For 35mm film, the focal plane is 24mm vertical by 36mm horizontal. For a DSLR, consult your manual.

Examine the photograph below. If you took the new hangar and used it as a ruler, the image would measure 4.33 "hangars" wide. From satellite imagery, the new hangar measures approximately 200ft x 500ft. However, the camera's view is not parallel to any surface of the hangar. We can approximate the "frontage" of the hangar presented to the camera by using the hypotenuse. [The diagonal for the trigonometric challenged.]  That would be 539ft. Multiply by 4.33 "hangars" to get a field of view is 2335ft, or 712 meters.

Focal Length = [Distance to Target] * [Focal Plane] / [Field of View]
Focal Length (meters) =  42000meters * 0.036meters / 712 meters =  2124mm
.

hangar rules

Plug the results into FCalc for a sanity check:

fcalc

Close enough for government work.